去掉重复sql

This commit is contained in:
sxu 2025-02-14 13:04:24 +08:00
parent c8a7c14cf7
commit 251b75b44a
1 changed files with 0 additions and 32 deletions

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@ -191,38 +191,6 @@
) )
</select> </select>
<!-- 查询用户详细信息 -->
<select id="queryCustInfo" resultType="com.bonus.core.customer.vo.CustInfoVo">
select ci.cust_limit_id,
<if test="info.serialNum != null and info.serialNum != ''">
ac.serial_num,
ac.card_status,
</if>
ci.alipay_contract_num,
<include refid="detailInfo"/>
from cust_info ci
left join cust_diet_like cd on ci.cust_id = cd.cust_id and cd.if_del = 2
left join acc_info ai on ci.cust_id = ai.cust_id
<if test="info.serialNum != null and info.serialNum != ''">
left join acc_card ac on ci.cust_id = ac.cust_id and ac.card_status in(1,4)
</if>
LEFT JOIN cust_place place ON ci.place_id = place.place_id
where 1 = 1
<if test="info.custId != null">
and ci.cust_id = #{info.custId}
</if>
<if test="info.custLimitId != null">
and ci.cust_limit_id = #{info.custLimitId}
</if>
<if test="info.serialNum != null and info.serialNum != ''">
and ac.serial_num = #{info.serialNum}
</if>
<if test="info.custState != null">
and ci.cust_state = #{info.custState}
</if>
</select>
<select id="getCustPayVO" resultType="com.bonus.core.customer.vo.CustPayVO"> <select id="getCustPayVO" resultType="com.bonus.core.customer.vo.CustPayVO">
SELECT a.cust_id, SELECT a.cust_id,
a.psn_type, a.psn_type,