update chinese_text_splitter.py
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@ -103,7 +103,8 @@ def similarity_search_with_score_by_vector(
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doc.page_content += doc0.page_content
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if not isinstance(doc, Document):
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raise ValueError(f"Could not find document for id {_id}, got {doc}")
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docs.append((doc, scores[0][j]))
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doc_score = min([scores[0][id] for id in [indices[0].tolist().index(i) for i in id_seq if i in indices[0]]])
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docs.append((doc, doc_score))
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torch_gc()
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return docs
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@ -50,6 +50,9 @@ PROMPT_TEMPLATE = """已知信息:
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根据上述已知信息,简洁和专业的来回答用户的问题。如果无法从中得到答案,请说 “根据已知信息无法回答该问题” 或 “没有提供足够的相关信息”,不允许在答案中添加编造成分,答案请使用中文。 问题是:{question}"""
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# 文本分句长度
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SENTENCE_SIZE = 100
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# 匹配后单段上下文长度
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CHUNK_SIZE = 250
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@ -1,19 +1,19 @@
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from langchain.text_splitter import CharacterTextSplitter
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import re
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from typing import List
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from configs.model_config import SENTENCE_SIZE
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class ChineseTextSplitter(CharacterTextSplitter):
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def __init__(self, pdf: bool = False, **kwargs):
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super().__init__(**kwargs)
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self.pdf = pdf
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def split_text(self, text: str) -> List[str]:
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def split_text1(self, text: str) -> List[str]:
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if self.pdf:
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text = re.sub(r"\n{3,}", "\n", text)
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text = re.sub('\s', ' ', text)
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text = text.replace("\n\n", "")
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sent_sep_pattern = re.compile('([﹒﹔﹖﹗.。!?]["’”」』]{0,2}|(?=["‘“「『]{1,2}|$))') # del :;
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sent_sep_pattern = re.compile('([﹒﹔;﹖﹗.。!?]["’”」』]{0,2}|(?=["‘“「『]{1,2}|$))') # del :;
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sent_list = []
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for ele in sent_sep_pattern.split(text):
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if sent_sep_pattern.match(ele) and sent_list:
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@ -22,4 +22,37 @@ class ChineseTextSplitter(CharacterTextSplitter):
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sent_list.append(ele)
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return sent_list
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def split_text(self, text: str) -> List[str]:
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if self.pdf:
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text = re.sub(r"\n{3,}", r"\n", text)
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text = re.sub('\s', " ", text)
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text = re.sub("\n\n", "", text)
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text = re.sub(r'([;;.!?。!?\?])([^”’])', r"\1\n\2", text) # 单字符断句符
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text = re.sub(r'(\.{6})([^"’”」』])', r"\1\n\2", text) # 英文省略号
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text = re.sub(r'(\…{2})([^"’”」』])', r"\1\n\2", text) # 中文省略号
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text = re.sub(r'([;;!?。!?\?]["’”」』]{0,2})([^;;!?,。!?\?])', r'\1\n\2', text)
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# 如果双引号前有终止符,那么双引号才是句子的终点,把分句符\n放到双引号后,注意前面的几句都小心保留了双引号
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text = text.rstrip() # 段尾如果有多余的\n就去掉它
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# 很多规则中会考虑分号;,但是这里我把它忽略不计,破折号、英文双引号等同样忽略,需要的再做些简单调整即可。
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ls = [i for i in text.split("\n") if i]
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for ele in ls:
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if len(ele) > SENTENCE_SIZE:
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ele1 = re.sub(r'([,,.]["’”」』]{0,2})([^,,.])', r'\1\n\2', ele)
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ele1_ls = ele1.split("\n")
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for ele_ele1 in ele1_ls:
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if len(ele_ele1) > SENTENCE_SIZE:
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ele_ele2 = re.sub(r'([\n]{1,}| {2,}["’”」』]{0,2})([^\s])', r'\1\n\2', ele_ele1)
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ele2_ls = ele_ele2.split("\n")
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for ele_ele2 in ele2_ls:
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if len(ele_ele2) > SENTENCE_SIZE:
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ele_ele3 = re.sub('( ["’”」』]{0,2})([^ ])', r'\1\n\2', ele_ele2)
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ele2_id = ele2_ls.index(ele_ele2)
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ele2_ls = ele2_ls[:ele2_id] + [i for i in ele_ele3.split("\n") if i] + ele2_ls[ele2_id + 1:]
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ele_id = ele1_ls.index(ele_ele1)
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ele1_ls = ele1_ls[:ele_id] + [i for i in ele2_ls if i] + ele1_ls[ele_id + 1:]
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id = ls.index(ele)
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ls = ls[:id] + [i for i in ele1_ls if i] + ls[id+1:]
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return ls
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